Pengaruh Beban Kerja Coder Dan Ketepatan Terminologi Medis Terhadap Keakuratan Kode Diagnosis Penyakit Gigi Di Rsj Grhasia Diy Tahun 2012
| Main Author: | Riyanti, Ning |
|---|---|
| Format: | Karya Ilmiah NonPeerReviewed application/pdf |
| Bahasa: | eng |
| Terbitan: |
, 2013
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| Subjects: | |
| Online Access: |
http://eprints.ums.ac.id/26185/1/Halaman_Depan.pdf http://eprints.ums.ac.id/26185/2/BAB_I.pdf http://eprints.ums.ac.id/26185/3/BAB_II.pdf http://eprints.ums.ac.id/26185/4/BAB_III.pdf http://eprints.ums.ac.id/26185/5/BAB_IV.pdf http://eprints.ums.ac.id/26185/6/BAB_V.pdf http://eprints.ums.ac.id/26185/7/BAB_VI.pdf http://eprints.ums.ac.id/26185/9/Daftar_Pustaka.pdf http://eprints.ums.ac.id/26185/12/Lampiran.pdf http://eprints.ums.ac.id/26185/13/Naskah_Publikasi.pdf http://eprints.ums.ac.id/26185/ |
Daftar Isi:
- Implementation officer with the border coding coding for data gathering from reporting, the results have not been confirmed coding with service providers. Luxasi coding group entry with the letter K is K05.5, there are problems that make coding a lack of understanding between the officers with service providers, medical terminology errors in the selection of approximately 10% which resulted in inaccurate diagnosis codes. K05.5 other periodontal diseases, dislocation of tooth S03.2. Research objectives: determine the effect of workload for the accuracy coder medical terminology RSJ Grhasia DIY in 2012. Research design used a time series approach. Object of study: DRM dental patients. Subject: coding clerk. Samples: the total sample of 1543 DRM. Analytic analysis: normality test datadengan Kolmogorov Smirnov test with the help of the computer program SPSS (Statistical Package for Social Science) for windows and multiple linear regression, the formula: Y = a + + b1X1 b2X2. RESULTS: The average time to encode the DRM = 14 minutes. Workload standard coder DRM 30 per day. There are significant workload variables ketapatan coder and medical terminology to code the accuracy of diagnosis of dental disease in the value of p = 0.006 (<0,05). Code Inaccurate 21.1%